Need to solve the following equation with three knowns and 2 unknowns. (2024)

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Prabhath Manuranga on 21 May 2024 at 6:00

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Commented: Torsten on 21 May 2024 at 11:46

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W0 = Wi + (1 - L)*Hi*gi

W0 and L is an unknowns.

Wi, Hi, and gi are the knowns with 172 values per each.

I want to find W0 and L and their standard deviations as well.

I want to get each values comes for W0 and L when the program runs.

But when this code runs i got 0 for standard deviation of both W10 and L. Is this code is right? Can anyone help me to solve this?

The following code was written.

Wi = Wi;

Unrecognized function or variable 'Wi'.

Hi = H_BM;

gi = g_mean;

% Define the objective function

fun = @(x) norm(Wi + (1 - x(1))*Hi.*gi - x(2));

% Set initial guess for L and W0

x0 = [0, 0];

% Solve the optimization problem

x = fminsearch(fun, x0);

% Extract the values of L and W0

L = x(1);

L

W0 = x(2);

W0

% Calculate standard deviation of W0 and L

std_W0 = std(W0);

std_W0

std_L = std(L);

std_L

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Rik on 21 May 2024 at 6:53

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You are calculating the standard deviation of a single value, not of the fit. fminsearch does not return the goodness of fit parameters with this syntax.

Prabhath Manuranga on 21 May 2024 at 7:49

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Could you please tell me how to fix it?

Rik on 21 May 2024 at 8:40

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Since you didn't post any data I can't show you what to do. You might want to try the fit function, since that will report the goodness of fit as the second output argument.

Prabhath Manuranga on 21 May 2024 at 9:07

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  • data123.xlsx

Please find the attached excel file for Wi, H_BM, and g_mean values.

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Answers (1)

Torsten on 21 May 2024 at 8:51

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H_BM = rand(100,1);

g_mean = rand(100,1);

Wi = rand(100,1);

Hi = H_BM;

gi = g_mean;

x = Hi.*gi;

y = Wi + Hi.*gi;

fitlm(x,y)

ans =

Linear regression model: y ~ 1 + x1Estimated Coefficients: Estimate SE tStat pValue ________ ________ ______ __________ (Intercept) 0.41233 0.043102 9.5664 1.0575e-15 x1 1.2316 0.15371 8.013 2.3796e-12Number of observations: 100, Error degrees of freedom: 98Root Mean Squared Error: 0.294R-squared: 0.396, Adjusted R-Squared: 0.39F-statistic vs. constant model: 64.2, p-value = 2.38e-12

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Prabhath Manuranga on 21 May 2024 at 9:29

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Edited: Prabhath Manuranga on 21 May 2024 at 9:30

Dear Mr. Torsten,

y= Wi + Hi.*gi; or y = Wi + (1-L)*Hi.*gi;

how to get two unknowns W0 and L, and their standard deviations here?

Torsten on 21 May 2024 at 9:33

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W0 = Estimate intercept

L = Estimate x1

SE = standard errors of the estimated parameters

For further details, consult the documentation of "fitlm".

Prabhath Manuranga on 21 May 2024 at 10:55

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Edited: Prabhath Manuranga on 21 May 2024 at 10:56

Need to solve the following equation with three knowns and 2 unknowns. (10)

Dear Mr. Torsten,

For this equation can i use the same method you mentioned above. Above equation there is no any Pi (because Pi = 1). but here i need to use Pi weight for the calculation.

Torsten on 21 May 2024 at 11:26

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Open in MATLAB Online

You have a linear regression equation

W0 + (L - 1)*Hi*gi = Wi

because if you set

W0 = a, L - 1 = b, Hi*gi = xi, Wi = yi

, your equation reads

a + b*x = y

You want to estimate a and b to make

sum_{i=1}^{i=172} (yi-(a+b*xi))^2

minimal.

This can be done via "fitlm" as I posted.

There are easier methods to get the coefficient a and b, but you wrote you also want statistical information about reliability etc.

Torsten on 21 May 2024 at 11:46

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Open in MATLAB Online

  • data123.xlsx

format long

M = readmatrix("data123.xlsx")

M = 10x3

1.0e+07 * 6.263682480329910 0.000000205900000 0.097810856393885 6.263657062323940 0.000002802300000 0.097812165123015 6.263669605757160 0.000001524500000 0.097811320851740 6.263624373910401 0.000006129800000 0.097810680733666 6.263620997894920 0.000006478400000 0.097810156445693 6.263650330102171 0.000003480200000 0.097811560786981 6.263682602864220 0.000000192100000 0.097810613817760 6.263680818837160 0.000000373000000 0.097808759764806 6.263617228951360 0.000006862700000 0.097809507129465 6.263661105500140 0.000002381500000 0.097808297704551

<mw-icon class=""></mw-icon>

<mw-icon class=""></mw-icon>

Wi = M(:,1);

H_BM = M(:,2);

g_mean = M(:,3);

Hi = H_BM;

gi = g_mean;

x = Hi.*gi;

y = Wi;

fitlm(x,y)

ans =

Linear regression model: y ~ 1 + x1Estimated Coefficients: Estimate SE tStat pValue _____________________ __ _____ ______ (Intercept) 62636844.9371338 0 Inf 0 x1 -1.00231759363032e-05 0 -Inf 0 Number of observations: 10, Error degrees of freedom: 8R-squared: 1, Adjusted R-Squared: 1F-statistic vs. constant model: 4.65e+06, p-value = 2.4e-24

n = numel(Wi);

Mat = [ones(n,1),x];

rhs = y;

sol = Mat\rhs;

W0 = sol(1)

W0 =

6.263684493713374e+07

L = 1 + sol(2)

L =

0.999989976824064

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